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Dyson number : ウィキペディア英語版
Parasitic number
An ''n''-parasitic number (in base 10) is a positive natural number which can be multiplied by ''n'' by moving the rightmost digit of its decimal representation to the front. Here ''n'' is itself a single-digit positive natural number. In other words, the decimal representation undergoes a right circular shift by one place. For example, 4•128205=512820, so 128205 is 4-parasitic. Most authors do not allow leading zeros to be used, and this article follows that convention. So even though 4•025641=102564, the number 025641 is ''not'' 4-parasitic.
== Derivation ==

An ''n''-parasitic number can be derived by starting with a digit ''k'' (which should be equal to ''n'' or greater) in the rightmost (units) place, and working up one digit at a time.
For example, for ''n'' = 4 and ''k'' = 7
:4•7=28
:4•87=348
:4•487=1948
:4•9487=37948
:4•79487=317948
:4•179487=717948.
So 179487 is a 4-parasitic number with units digit 7. Others are 179487179487, 179487179487179487, etc.
Notice that the repeating decimal
:x=0.179487179487179487\ldots=0.\overline \mbox4x=0.\overline=\frac.
Thus
:4x=\frac \mbox x=\frac.
In general, an ''n''-parasitic number can be found as follows. Pick a one digit integer ''k'' such that , and take the period of the repeating decimal ''k''/(10''n''−1).
This will be \frac(10^m-1)
where ''m'' is the length of the period; i.e. the multiplicative order of 10 modulo .
For another example, if ''n'' = 2, then 10''n'' − 1 = 19 and the repeating decimal for 1/19 is
: \frac=0.\overline.
So that for 2/19 is double that:
: \frac=0.\overline.
The length ''m'' of this period is 18, the same as the order of 10 modulo 19, so = 105263157894736842.
105263157894736842 × 2 = 210526315789473684, which is the result of moving the last digit of 105263157894736842 to the front.

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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